Re: stereoscopic CAVE rendering in Performer

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Don Burns (don_burns++at++peru.engr.sgi.com)
Thu, 16 Sep 1999 11:41:35 -0700 (PDT)

Yohan,

Please re-read my last post. The answer is there.

>From your diagram, place a point on line AB where the "View direction" vector
will intersect it. Call this G. Place another point H on AB such that a line
VH will intersect perpendicular to AB. Assuming the width of the screen is B -
A, m = -(H - G)/(B - A). Apply the rest and you'll have it.

-don

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