Re: [info-performer] C/C++ typecast problem

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From: faculaganymede (faculaganymede++at++yahoo.com)
Date: 02/17/2004 15:26:15

Thank you, Manuel. What does (*) do?

> char **temp[2];
> fun ((const char *(*)[2]) temp);

The compiler builds this okay, but I got run-time
errors. This is my simple program, please let me know
if you find an error:
---------------------------------------------
#include <stdio.h>
#include < stdlib.h>
#include <string.h>

void fun(const char *fnames[][2]);

int main( )
{

        char **temp[2];
        int n=10;

        temp[0]=(char**)malloc(sizeof(char*)*n);
        temp[1]=(char**)malloc(sizeof(char*)*n);
        for(int i=0; i<n; i++)
        {
                temp[0][i]=(char*)malloc(sizeof(char)*256);
                temp[1][i]=(char*)malloc(sizeof(char)*256);

                strcpy(temp[0][i], "hello 1");
                strcpy(temp[1][i], "hello 2");
        }

        fun((const char*(*)[2])temp);
}

void fun(const char *fnames[][2])
{
        int n=10;

        for(int i=0; i<2; i++)
        {
                for(int j=0; j<n; j++)
                {
                        printf("%s\n", fnames[i][j]);
                }
        }
}
---------------------------------------------

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