Hello Krishna,
In 'Case 3' Change the line
jiffies = start + HZ - 1;
to
jiffies = start + HZ - 91;
and see the difference.
Regards,
Vino.
On Thu, 8 Nov 2001, Krishna Kumar wrote:
>
> Hi Linus,
>
> > >
> > > In short: It is wrong to do
> > >
> > > if (jiffies <= start+HZ)
> > >
> > > and it is _right_ to do
> > >
> > > if (jiffies - start <= HZ)
> >
> > Actually this last part is wrong, isn't it ? jiffies <= start + HZ is
> also
> > a correct way to do it, since start+HZ will overflow to the current value
> > of jiffies when HZ time elapses. So the above two statements are
> IDENTICAL.
> >
> > No.
> >
> > Try it out with a few examples. You'll see.
> >
> > Linus
>
> I am sorry, but I still don't see the difference. I wrote a small program
> with different
> cases, but the values still come same irrespective of the input arguments
> to the
> checks. Could you tell under what conditions the checks wuold fail ? The
> 2's
> complement works the same for addition and subtraction. I have included
> the
> test program below.
>
> Thanks,
>
> - KK
>
> ---------------------------------------------------------------------------------------------
> /*
> if (jiffies <= start+HZ)
> if (jiffies - start <= HZ)
> */
>
> #define HZ 100
>
> main()
> {
> unsigned long start, jiffies;
>
> /* Case 1 */
> start = ((unsigned long) -1);
> jiffies = start + HZ;
> if (jiffies <= start + HZ) {
> printf("Less Case 1\n");
> }
> if (jiffies - start <= HZ) {
> printf("Less Case 2\n");
> }
>
> /* Case 2 */
> start = ((unsigned long) -10);
> jiffies = start + HZ + 1;
> if (jiffies <= start + HZ) {
> printf("Less Case 3\n");
> }
> if (jiffies - start <= HZ) {
> printf("Less Case 4\n");
> }
>
> /* Case 3 */
> start = ((unsigned long) -10);
> jiffies = start + HZ - 1;
> if (jiffies <= start + HZ) {
> printf("Less Case 5\n");
> }
> if (jiffies - start <= HZ) {
> printf("Less Case 6\n");
> }
> }
>
>
>
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