From 1bd4906c7d8928cb1571667a8a331e6ad2c69daa Mon Sep 17 00:00:00 2001 From: Roman Ovchinnikov Date: Sat, 21 May 2011 04:05:33 +0400 Subject: [PATCH] adding example with xfs_info decryption, v2 Signed-off-by: Roman Ovchinnikov --- man/man8/xfs_growfs.8 | 37 +++++++++++++++++++++++++++++++++++++ 1 files changed, 37 insertions(+), 0 deletions(-) diff --git a/man/man8/xfs_growfs.8 b/man/man8/xfs_growfs.8 index 02793ae..e5f825a 100644 --- a/man/man8/xfs_growfs.8 +++ b/man/man8/xfs_growfs.8 @@ -1,3 +1,14 @@ +.\" Verbatim blocks taken from openssl req manpage content +.de Vb \" Begin verbatim text +.ft CW +.nf +.ne \\$1 +.. +.de Ve \" End verbatim text +.ft R +.fi +.. + .TH xfs_growfs 8 .SH NAME xfs_growfs, xfs_info \- expand an XFS filesystem @@ -105,6 +116,7 @@ this is specified with Specifies that no change to the filesystem is to be made. The filesystem geometry is printed, and argument checking is performed, but no growth occurs. +.B See output examples below. .TP .BI "\-r | \-R " size Specifies that the real-time section of the filesystem should be grown. If the @@ -152,6 +164,31 @@ reside. In order to grow a filesystem, it is necessary to provide added space for it to occupy. Therefore there must be at least one spare new disk partition available. Adding the space is often done through the use of a logical volume manager. +.SH "EXAMPLES" + +Understanding xfs_info output. +.PP +Let's assume one have the next xfs_info /dev/sda output: +.PP +.Vb 1 +\& meta-data=/dev/sda isize=256 agcount=32, agsize=16777184 blks +\& = sectsz=512 attr=2 +\& data = bsize=4096 blocks=536869888, imaxpct=5 +\& = sunit=32 swidth=128 blks +\& naming =version 2 bsize=4096 +\& log =internal bsize=4096 blocks=32768, version=2 +\& = sectsz=512 sunit=32 blks, lazy-count=1 +\& realtime =none extsz=524288 blocks=0, rtextents=0 +.Ve +.PP + +Here, the data section of the output indicates "bsize=4096", +meaning the data block size for this filesystem is 4096 bytes. +This section also shows "sunit=32 swidth=128 blks", which means +the stripe unit is 32*4096 bytes = 128 kibibytes and the stripe +width is 128*4096 bytes = 512 kibibytes. +A single stripe of this filesystem therefore consists +of four stripe units (128 blocks / 32 blocks per unit). .SH SEE ALSO .BR mkfs.xfs (8), .BR md (4), -- 1.7.2.5