| To: | xfs@xxxxxxxxxxx |
|---|---|
| Subject: | Re: Calculating swidth On A RAID6 Volume |
| From: | Emmanuel Florac <eflorac@xxxxxxxxxxxxxx> |
| Date: | Tue, 20 Jul 2010 16:44:44 +0200 |
| In-reply-to: | <4C45AF09.5090901@xxxxxxxxxxxx> |
| Organization: | Intellique |
| References: | <3C5E029826A0704DB5998577FCFF46F0094DA1AD69@dagobah> <201007201522.39455@xxxxxx> <4C45AF09.5090901@xxxxxxxxxxxx> |
Le Tue, 20 Jul 2010 16:13:29 +0200
Michael Weissenbacher <mw@xxxxxxxxxxxx> écrivait:
>
> IIRC sunit and swidth are both specified in units of 512 bytes (don't
> ask me why)
Because this is the disk block size for all disks drives ever made
except the very latest ones (4096 bytes blocks) and the special
RAID-formatted 520 bytes sometimes in use in the past.
> so a sunit value of 512 would mean 256KB stripe size which
> is correct :-)
exactly. Or use su and sw to specify the size in k, m, etc.
--
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