| To: | ahu@xxxxxxx |
|---|---|
| Subject: | Re: How to get IPv6 interface? |
| From: | YOSHIFUJI Hideaki / 吉藤英明 <yoshfuji@xxxxxxxxxxxxxx> |
| Date: | Thu, 28 Nov 2002 21:13:37 +0900 (JST) |
| Cc: | netdev@xxxxxxxxxxx |
| In-reply-to: | <20021128111600.GA30967@outpost.ds9a.nl> |
| Organization: | USAGI Project |
| References: | <004c01c29679$52812600$6c06a8c0@zhengjp> <8120000.1038471604@gate.muc.bieringer.de> <20021128111600.GA30967@outpost.ds9a.nl> |
| Sender: | netdev-bounce@xxxxxxxxxxx |
In article <20021128111600.GA30967@xxxxxxxxxxxxxxx> (at Thu, 28 Nov 2002 12:16:00 +0100), bert hubert <ahu@xxxxxxx> says: > > > I'm writing an IPv6 application, so which function can get the IPv6 > > > inteface information? And how to call it? > > > > Sorry, I'm not really an IPv6 programmer, hopefully others can help > > you. > > The best way is probably to look at the 'ip' sources which use netlink to > query the kernel. You may want to use getifaddrs() in USAGI libinet6. -- Hideaki YOSHIFUJI @ USAGI Project <yoshfuji@xxxxxxxxxxxxxx> GPG FP: 9022 65EB 1ECF 3AD1 0BDF 80D8 4807 F894 E062 0EEA |
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