| To: | stan@xxxxxxxxxxxxxxxxx |
|---|---|
| Subject: | Re: swidth in RAID |
| From: | aurfalien <aurfalien@xxxxxxxxx> |
| Date: | Sun, 30 Jun 2013 15:36:06 -0700 |
| Cc: | xfs@xxxxxxxxxxx |
| Delivered-to: | xfs@xxxxxxxxxxx |
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| In-reply-to: | <51D0A62E.2020309@xxxxxxxxxxxxxxxxx> |
| References: | <557F888F-34EA-4669-B861-C0B684DAD13D@xxxxxxxxx> <51D0A62E.2020309@xxxxxxxxxxxxxxxxx> |
On Jun 30, 2013, at 2:42 PM, Stan Hoeppner wrote: > On 6/30/2013 1:43 PM, aurfalien wrote: > >> I understand swidth should = #data disks. > > No. "swidth" is a byte value specifying the number of 512 byte blocks > in the data stripe. > > "sw" is #data disks. > >> And the docs say for RAID 6 of 8 disks, that means 6. >> >> But parity is distributed and you actually have 8 disks/spindles working for >> you and a bit of parity on each. >> >> So shouldn't swidth equal disks in raid when its concerning distributed >> parity raid? > > No. Lets try visual aids. > > Set 8 coffee cups (disk drives) on a table. Grab a bag of m&m's. > Separate 24 blues (data) and 8 reds (parity). But are the cups 8oz, 16oz or smaller/larger? Ceramic, plastic, glass, etc...? Actually I really enjoyed the visual aid, many many thanks. - aurf |
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