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Re: Output of mkfs.xfs su/sw values don't match the command line su/sw v

To: Nathan Scott <nathans@xxxxxxx>
Subject: Re: Output of mkfs.xfs su/sw values don't match the command line su/sw values
From: Justin Piszcz <jpiszcz@xxxxxxxxxxxxxxx>
Date: Sun, 9 Jul 2006 16:59:48 -0400 (EDT)
Cc: Brian Davis <bridavis@xxxxxxxxxxx>, xfs@xxxxxxxxxxx
In-reply-to: <20060709121321.C1648127@wobbly.melbourne.sgi.com>
References: <44AFF7AA.2040001@comcast.net> <20060709121321.C1648127@wobbly.melbourne.sgi.com>
Sender: xfs-bounce@xxxxxxxxxxx

On Sun, 9 Jul 2006, Nathan Scott wrote:

On Sat, Jul 08, 2006 at 02:21:30PM -0400, Brian Davis wrote:
localhost ~ # mkfs.xfs -f -d sunit=128,swidth=256 /dev/sda1
meta-data=/dev/sda1              isize=256    agcount=32, agsize=4578992
         =                       sectsz=512   attr=0
data     =                       bsize=4096   blocks=146527744, imaxpct=25
         =                       sunit=16     swidth=32 blks, unwritten=1
naming   =version 2              bsize=4096
log      =internal log           bsize=4096   blocks=32768, version=1
         =                       sectsz=512   sunit=0 blks
realtime =none                   extsz=65536  blocks=0, rtextents=0

Why does the output display the sunit=16 and swidth=32 when I wanted it
configured with 128 and 256 respectively? It looks like the output is
displaying the fs block size (4096) rather than 512 blocks specified on
the command line and the man page.
Is this correct?

Thats correct. Odd, isn't it? Dunno why it was done this way (waay before my time) ... its been like that forever though.



You have to subtract/divide the units by a certain number, the PAGE SIZE or something, I do not have the docs in front of me but that is why it converts it, also, I have found mkfs.xfs default options automatically optimize for the number of drives in the raid (at least with SW raid).


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