|Subject:||Re: on the wire behaviour of TSO on/off is supposed to be the same yes?|
|From:||Rick Jones <rick.jones2@xxxxxx>|
|Date:||Mon, 24 Jan 2005 13:22:23 -0800|
|References:||<41F1516D.5010101@xxxxxx> <200501211358.53783.jdmason@xxxxxxxxxx> <41F163AD.5070400@xxxxxx> <20050121124441.76cbbfb9.davem@xxxxxxxxxxxxx> <41F17B7E.2020002@xxxxxx> <20050121141820.7d59a2d1.davem@xxxxxxxxxxxxx> <41F186A8.9030805@xxxxxx> <20050121204948.034b2510.davem@xxxxxxxxxxxxx> <41F55B93.6040603@xxxxxx> <20050124124353.2f760e1a.davem@xxxxxxxxxxxxx>|
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David S. Miller wrote:
Becuase we disable TSO on any packet loss whatsoever, we can predict exactly what the CWND will be at the time a packet is sent.
I'd heard someone else mention that, but wasn't sure. Now I know I guess. I can see how that would simplify things considerably, although it may have some non-technical implications...
When we take away that invariant, which we do want to do, we'll need to tweak how this works.
OK. BTW, how "hard" is it to reference chunks of a big buffer and send them? Particularly in a situation where there is TSO which implies SG and CKO.
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